CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING)

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CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING)

CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING)

Discuss CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) within the Quant forums, part of the CAT, XAT, MAT, CET, JMET and other Indian MBA Entrance Exams category; Originally Posted by gaurav200x
how can i be wrong in the 1st one... the last digits have to be 72 ...

The given number should be divisible by both 9 & 4
Thus, as per the rule ,
I] DIVISIBILITY TEST FOR 4 -
A number is divisible by 4 when the number formed by the last two rigjht hand digits is divisible by 4 or if the last two digits are 0's.

II] DIVISIBILTY TEST FOR 9 -
A number is divisible by 9 when the sum of its digits is divisible by 9.

Therefore, 3+0+5+1+4+3+2+A = 18+A

If we take 9 (Option 4), then sum of digits (i.e. 27/9 = 3) is divisible by 9
[as per II] &
last two right hand digits (i.e. 92/4 = 23) is divisible by 4 [as per I].

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Re: CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) -
August 23rd, 2006

If a and b are two prime nos it can take the values
78 as it is the addition of two prime nos 61,17i.e 61+17=78
Similarly 7 can be expressed as the addition of 2 and 5
The last no 23 cannot be expressed as the addition of any two prime nos.
So the correct option is 3 i.e 1 and 2 only

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Re: CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) -
August 24th, 2006

The ans to question no 3 is d)none of these as
9+49=58 which ends in 8 and 81+1=82 which ends in 2 so 1 statement in not true
Similarly 1+8=9 which is the sumof the cubes of 1 and 2 ends in 9 ans 216+27 which is the sum of cubes of 6 and 3 ends in 9
also the sum of 100+1000 ends in 0 so the third statement is false

Re: CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) -
August 24th, 2006

The ans to the 4 problem is option 2)I, II, IV, V.
847+53=900 which is the square of 30.
847*7=5929 which is the sqaure of 77.
847/11=77 which is not a perfect square.
847/7=121 which is the square of 11.
847-6=841 which is the square of 29
PSlz give the ans for the first 2 questions

Re: CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) -
August 24th, 2006

Quote:

Originally Posted by neeraj_uchila

The ans to question no 3 is d)none of these as
9+49=58 which ends in 8 and 81+1=82 which ends in 2 so 1 statement in not true
Similarly 1+8=9 which is the sumof the cubes of 1 and 2 ends in 9 ans 216+27 which is the sum of cubes of 6 and 3 ends in 9
also the sum of 100+1000 ends in 0 so the third statement is false

good, neeraj , answer for Q. 3 is correct...
good going...

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Re: CRACK THE CAT - DOUBT OVER MATHS (PROBLEM SOLVING) -
August 24th, 2006

Quote:

Originally Posted by neeraj_uchila

The ans to the 4 problem is option 2)I, II, IV, V.
847+53=900 which is the square of 30.
847*7=5929 which is the sqaure of 77.
847/11=77 which is not a perfect square.
847/7=121 which is the square of 11.
847-6=841 which is the square of 29
PSlz give the ans for the first 2 questions

Thanx, neeraj. Good answer.
i'm not sure abt this question...
let gaurav give answers...for 1 & 2...

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