deepakraam
Par 100 posts (V.I.P)
Sq(1+sq(2+sq(3+sq(4+......)=?
sq=squareroot.
-Deepak.
sq=squareroot.
-Deepak.
hey ver r d options (hehehe!!!!!!!!!!)deepakraam said:Sq(1+sq(2+sq(3+sq(4+......)=?
sq=squareroot.
-Deepak.
would be glad if u can give a proper n complete solution...pratik_mehta7 said:(2+sq(3+sq(4+......) <=== take it as x n solve
kartik said:Pratik needed on this thread
deepakraam said:Sq(1+sq(2+sq(3+sq(4+......)=?
sq=squareroot.
-Deepak.
maheshbhatacharya said:one doubt mr aspire........how did u take sqr(4+sqr(5+..........)) as sqr 4and hence as 2???could u explain that??
its an inequation problem.
between what values of x, is the expression 19x-2x^2-35 positive?
is the answer (5/2)<x<7 correct?
thanks gaurav.
but can you please tell me how to decide which one term to be taken as <0 and which one as >0
It'll be easier to know that once we know what is your approach in solving the problemcan anybody solve this question
( ratio & proportion )
Q. Amit and Binit enter into a partnership Amit
invested the captial amounting to Rs. 4500 with
the condition that the profit is to be equally divided
and that Binit pays interest on half of the capital
to Amit at 10% but receives Rs 120 per month for
carrying on the business .what is their total yearly
profit if Binit's income is half of amit's income ?
(a) 9,180 (b) 9,000 (c) 9356 (d) 10,000
I am not so sure but, I think that the answer --- (a)
but can somebady explain it ...