CAT : PROBLEM SOLVING - PERCENTAGES

Hey, MPians............ I'm back with CAT threads again.............

Please post ur answers as well as put ur questions here also, especially for CAT 2007 aspirants...............

PERCENTAGES

1. Ryan’s stock of goods is worth $ 9462, which is 15 % more than Harland’s, and 15 % less than Lambert’s. What is the value of stock carried by Harland and Lambert respectively?

1] $ 8218, $ 10032
2] $ 1419, $ 10881
3] $ 8042, $ 10881
4] $ 8228, $ 11132

2. An electrical contractor purchases a certain amount of wire, 10 % of which was stolen. After using 85 % of the remainder, he had 47m and 25 cm of wire left. How much wire did he purchase?

1] 325m
2] 350m
3] 96m
4] 103m

3. The population of two parts of a town i.e. the upper and the lower parts of a town were equal. After the former had fallen 20 per cent, the total number of inhabitants was 39390. What was the population of each part at first?

1] 32825
2] 20200
3] 21435
4] 76810

4. A fraction in reduced form is such that when it is squared and then the numerator is reduced by 100/3 % and the denominator is reduced by 20%, its result is twice the original fraction. The sum of the numerator and the denominator is :-

1] 8
2] 17
3] 13
4] None of these

5. Which of the following statement/s is/are true?

I – If two numbers are such that one is 25 % more than the second then the sum of the two numbers is nine times that of the difference of the two numbers.

II – If 56 % of a number A is 24 % of another number B then 49 % of A is 21 % of B.

III – If 7/11 x is same as 2/9 y, then 81 % of x is same as 188/7 of y.

1] Only I.
2] Only III.
3] Only I and II.
4] Only II and III.

nice post......................... dude nice work but the answers could be helpfull

nice work friend
here are my answers please tell me whethe i am correct or not....
1)1
2)2
3)3
4)didn't get
5)3
Please give a clue for 4th problem..
thanks.. keep up the good work going....

here is my answer...it might be wrong..so please check.thanks in advance..
1)1
2)2
3)3

for the fourth one ..
what u need to do is
assume the fraction in reduced form as a/b . now according to question { a^2 - 1/3 X a^2 } / {b^2 - 1/5 X b^2} = 2a/b.

solve it ,u'll get a/b=12/5
answer is -> 12+5 =17