rahul_parab2006
MP Guru
gaurav200x said:how can i be wrong in the 1st one... the last digits have to be 72 to be divisible by 3. 32, 52 or 92 can't be
and for the last one... I too thought about I and III but i dun think I is completely true... bcoz 1 is not included.
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LET ME ANSWER FOR Q. 1) -
The given number should be divisible by both 9 & 4
Thus, as per the rule ,
I] DIVISIBILITY TEST FOR 4 -
A number is divisible by 4 when the number formed by the last two rigjht hand digits is divisible by 4 or if the last two digits are 0's.
II] DIVISIBILTY TEST FOR 9 -
A number is divisible by 9 when the sum of its digits is divisible by 9.
Therefore, 3+0+5+1+4+3+2+A = 18+A
If we take 9 (Option 4), then sum of digits (i.e. 27/9 = 3) is divisible by 9
[as per II] &
last two right hand digits (i.e. 92/4 = 23) is divisible by 4 [as per I].
Hence, answer is 4] 9. .